What is the slope ofintercept f(x)=-0.388x+170.96 ?

The slope ofintercept f(x)=-0.388x+170.96 is f(x)=-0.388x+170.96

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slope ofintercept f(x)=-0.388x+170.96

slope intercept

f (x) = - 0.388 x + 170.96

f (x) = - 0.388 x + 170.96

Solution steps

f (x) = - 0.388 x + 170.96

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

f (x) = - 0.388 x + 170.96

f (x) = ln (5 - 6 x^{2})

f (x) = \frac{x ^{2} + 4}{x - 2}

3 x + 3 y = 24

f (x) = \frac{2}{( x - 4 ) ( - x + 6 )}

f (x) = x + 2 - 9

What is the slope ofintercept f(x)=-0.388x+170.96 ?
The slope ofintercept f(x)=-0.388x+170.96 is f(x)=-0.388x+170.96