What is the inverse of f(x)= 1/5 (x+18)^3-4 ?

The inverse of f(x)= 1/5 (x+18)^3-4 is \sqrt[3]{5x+20}-18

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inverse of f(x)= 1/5 (x+18)^3-4

inverse

f (x) = \frac{1}{5} (x + 18)^{3} - 4

Solution steps

y = \frac{1}{5} (x + 18)^{3} - 4

Replace

x

with

y

x = \frac{1}{5} (y + 18)^{3} - 4

Solve for

y, x = \frac{1}{5} (y + 18)^{3} - 4

\frac{x + 5}{x ^{2} - 16}

\frac{x ^{2} + 3}{2}

y = x (x - 4)

f (x) = \frac{1}{x ^{2} + 3 x - 10}

f (x) = \frac{x - 1}{x + 3}

What is the inverse of f(x)= 1/5 (x+18)^3-4 ?
The inverse of f(x)= 1/5 (x+18)^3-4 is \sqrt[3]{5x+20}-18