What is the domain of f(x)= 1/4 sqrt(x-3)+6 ?

The domain of f(x)= 1/4 sqrt(x-3)+6 is x>= 3

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domain of f(x)= 1/4 sqrt(x-3)+6

domain

f (x) = \frac{1}{4} x - 3 + 6

x \geq 3

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{x - 2}{5 - x}

f (x) = x 100 - x^{2}

f (x) = 2 x - 4

(2, 1), (9, 0)

f (x) = 4 cos (\frac{π}{3} x)

What is the domain of f(x)= 1/4 sqrt(x-3)+6 ?
The domain of f(x)= 1/4 sqrt(x-3)+6 is x>= 3