Solution
midpoint
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intercepts of f(x)=-6x^2+384intercepts domain of f(x)=(x^2+2)/(3x^2-1)domain monotone f(x)=(e^x)/xmonotone intervals y=cot(x)range of f(x)=-sqrt(x+3)-2range
Frequently Asked Questions (FAQ)
What is the midpoint (-3,6),(5,-6) ?
The midpoint (-3,6),(5,-6) is (1,0)