What is the inverse of f(x)=2*x^2+x-2 ?

The inverse of f(x)=2*x^2+x-2 is (-1+sqrt(8x+17))/4 ,(-1-sqrt(8x+17))/4

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inverse of f(x)=2*x^2+x-2

inverse

f (x) = 2 \cdot x^{2} + x - 2

\frac{- 1 + 8 x + 17}{4}, \frac{- 1 - 8 x + 17}{4}

Solution steps

y = 2 x^{2} + x - 2

Replace

x

with

y

x = 2 y^{2} + y - 2

Solve for

y, x = 2 \cdot y^{2} + y - 2

\frac{- 1 + 8 x + 17}{4}, \frac{- 1 - 8 x + 17}{4}

- (\frac{1}{3})^{x + 4}

f (x) = \frac{4 x - 3}{6 - 5 x}

\frac{1}{x - 2}

3 x^{\frac{1}{3}}

(11, - 3), (- 10, 2)

What is the inverse of f(x)=2*x^2+x-2 ?
The inverse of f(x)=2*x^2+x-2 is (-1+sqrt(8x+17))/4 ,(-1-sqrt(8x+17))/4