What is the domain of 1/(7x^3-5x) ?

The domain of 1/(7x^3-5x) is x sqrt(5/7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(7x^3-5x)

domain

\frac{1}{7 x ^{3} - 5 x}

x < - \frac{5}{7} or - \frac{5}{7} < x < 0 or 0 < x < \frac{5}{7} or x > \frac{5}{7}

Interval Notation

(- \infty, - \frac{5}{7}) \cup (- \frac{5}{7}, 0) \cup (0, \frac{5}{7}) \cup (\frac{5}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - \frac{5}{7}, x = \frac{5}{7}

The function domain

x < - \frac{5}{7} or - \frac{5}{7} < x < 0 or 0 < x < \frac{5}{7} or x > \frac{5}{7}

\frac{( x + 10 )}{x ^{2} - 100}

f (x) = \frac{2 x ^{2} - 3 x - 2}{x ^{2} - 4}

x - 2 y = 12, (- 8, - 7)

f (x) = \frac{x}{x ^{2} + 6 x + 8}

y = x^{2} - 2 x - 3

What is the domain of 1/(7x^3-5x) ?
The domain of 1/(7x^3-5x) is x<-sqrt(5/7)\lor-sqrt(5/7)<x<0\lor 0<x<sqrt(5/7)\lor x>sqrt(5/7)