What is the domain of ((x^2+x-2))/(2x^2-2) ?

The domain of ((x^2+x-2))/(2x^2-2) is x 1

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domain of ((x^2+x-2))/(2x^2-2)

domain

\frac{( x ^{2} + x - 2 )}{2 x ^{2} - 2}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

(0, 4), (10, 6)

f (x) = \frac{- 2 x + 8}{x ^{2} - 6 x + 8}

\frac{x + 4}{x - 5}

f (x) = 13 ln (x^{2} + 1) - 5 x

ln (11 x^{2} + 3)

What is the domain of ((x^2+x-2))/(2x^2-2) ?
The domain of ((x^2+x-2))/(2x^2-2) is x<-1\lor-1<x<1\lor x>1