What is the line (290,290.16),(295,295.17) ?

The line (290,290.16),(295,295.17) is y=1.002x-0.42

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line (290,290.16),(295,295.17)

line

(290, 290.16), (295, 295.17)

y = 1.002 x - 0.42

Solution steps

Find the line

y = mx + b

passing through

(290, 290.16)

(295, 295.17)

Compute the slope

(290, 290.16), (295, 295.17) : m = 1.002

Compute the

y

intercept:

b = - 0.42

Construct the line equation

y = mx + b

where

m = 1.002

and

b = - 0.42

y = 1.002 x - 0.42

- 3 x^{5} + 2 x^{2} - 7 x + 1

f (x) = 3 - 2 x

f (x) = \frac{( - 2 x + 5 )}{3}

f (x) = \frac{2 + x}{x + 1}

\frac{1 + x}{1 - e ^{- x}} - \frac{1}{x}

What is the line (290,290.16),(295,295.17) ?
The line (290,290.16),(295,295.17) is y=1.002x-0.42