What is the perpendicular y=-3x+1,(-6,-2) ?

The perpendicular y=-3x+1,(-6,-2) is y= 1/3 x

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perpendicular y=-3x+1,(-6,-2)

perpendicular

y = - 3 x + 1, (- 6, - 2)

y = \frac{1}{3} x

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 3 x + 1

that passes through

(- 6, - 2)

Find the slope of

y = - 3 x + 1 : m = - 3

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(- 6, - 2) : y = \frac{1}{3} x

y = \frac{1}{3} x

- ln (x)

\frac{x ^{2} - 1}{x ^{3} - 9 x}

x + 5 - x

(3.2, 0.167), (3.25, 0.177)

f (x) = 1 - x

What is the perpendicular y=-3x+1,(-6,-2) ?
The perpendicular y=-3x+1,(-6,-2) is y= 1/3 x