What is the range of f(x)=log_{2}(x+1)-3 ?

The range of f(x)=log_{2}(x+1)-3 is -infinity <f(x)<infinity

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range of f(x)=log_{2}(x+1)-3

range

f (x) = lo g_{2} (x + 1) - 3

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of a logarithmic function of the form

c \cdot lo g (a x + b) + k

is all the real numbers

- \infty < f (x) < \infty

y = \frac{x}{2} + 1

f (x) = \frac{s - 1}{s - 4}

(- 5, 5), (3, - 5)

f (x) = lo g_{e} (2 - x)

f (x) = 2 x^{2} + 24 x - 74

What is the range of f(x)=log_{2}(x+1)-3 ?
The range of f(x)=log_{2}(x+1)-3 is -infinity <f(x)<infinity