What is the monotone f(x)= x/(sqrt(x)-1) ?

The monotone f(x)= x/(sqrt(x)-1) is Decreasing:0<= x<1,Decreasing:1<x<4,Increasing:4<x<infinity

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monotone f(x)= x/(sqrt(x)-1)

monotone intervals

f (x) = \frac{x}{x - 1}

Decreasing : 0 \leq x < 1, Decreasing : 1 < x < 4, Increasing : 4 < x < \infty

Solution steps

f^{'} (x) = \frac{x - 2}{2 ( x - 1 ) ^{2}}

Find intervals:

Decreasing

: 0 \leq x < 1,

Decreasing

: 1 < x < 4,

Increasing

: 4 < x < \infty

Decreasing : 0 \leq x < 1, Decreasing : 1 < x < 4, Increasing : 4 < x < \infty

f (x) = (x^{\frac{1}{2}} + 7)^{3}

\frac{x - 4}{x - 2}

f (x) = 2 x^{2} + x - 14

- 2 x^{2} + 6 x

y = - \frac{1}{3} x + 2

What is the monotone f(x)= x/(sqrt(x)-1) ?
The monotone f(x)= x/(sqrt(x)-1) is Decreasing:0<= x<1,Decreasing:1<x<4,Increasing:4<x<infinity