What is the domain of sqrt(x^2-4) ?

The domain of sqrt(x^2-4) is x = 2

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domain of sqrt(x^2-4)

domain

x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = - 4 x^{4} + 8 x^{3}

f (x) = x^{3} + 2 x^{2} - 4 x - 8

x^{2} - 8 x

f (x) = x^{3} - 8

\frac{5 x - 6}{9 x + 1}

What is the domain of sqrt(x^2-4) ?
The domain of sqrt(x^2-4) is x<=-2\lor x>= 2