What is the range of f(x)=x^3-8 ?

The range of f(x)=x^3-8 is -infinity <f(x)<infinity

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range of f(x)=x^3-8

range

f (x) = x^{3} - 8

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of polynomials with odd degree is all the real numbers

- \infty < f (x) < \infty

\frac{5 x - 6}{9 x + 1}

f (x) = \frac{3}{x ^{2} - 9}

\frac{x ^{2} + x - 6}{x ^{2} + 2 x - 3}

f (x) = x 2 - 10 x + 16

\frac{x}{2 x ^{2} + 4}

What is the range of f(x)=x^3-8 ?
The range of f(x)=x^3-8 is -infinity <f(x)<infinity