What is the domain of y=sqrt(2x+1) ?

The domain of y=sqrt(2x+1) is x>=-1/2

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domain of y=sqrt(2x+1)

domain

y = 2 x + 1

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

y = ∣ x - 3 ∣

f (x) = \frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

(- 6, - 2), (- 4, 0)

f (x) = 6 + x

f (x) = \frac{( 2 )}{( x - 2 )}