What is the domain of f(x)=sqrt(36-x^2)+sqrt(x^2-25) ?

The domain of f(x)=sqrt(36-x^2)+sqrt(x^2-25) is -6<= x<=-5\lor 5<= x<= 6

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domain of f(x)=sqrt(36-x^2)+sqrt(x^2-25)

domain

f (x) = 36 - x^{2} + x^{2} - 25

- 6 \leq x \leq - 5 or 5 \leq x \leq 6

Interval Notation

[- 6, - 5] \cup [5, 6]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq - 5 or 5 \leq x \leq 6

The function domain

- 6 \leq x \leq - 5 or 5 \leq x \leq 6

(2.4) (4.2)

f (x) = \frac{4 x + 20}{x ^{2} + 5 x}

\frac{1}{4} x + 5

f (x) = 3 sin (2 x) + cos (\frac{x}{2})

x^{7}

What is the domain of f(x)=sqrt(36-x^2)+sqrt(x^2-25) ?
The domain of f(x)=sqrt(36-x^2)+sqrt(x^2-25) is -6<= x<=-5\lor 5<= x<= 6