What is the domain of y=sqrt((2x-4)/3) ?

The domain of y=sqrt((2x-4)/3) is x>= 2

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domain of y=sqrt((2x-4)/3)

domain

y = \frac{2 x - 4}{3}

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = x^{2} - 5 x

x^{3} - 3 x

f (x) = - tan (x + 6) - 5

f (x) = \frac{8}{\frac{3}{x} - 1}

(- 5, 5), (2, - 5)

What is the domain of y=sqrt((2x-4)/3) ?
The domain of y=sqrt((2x-4)/3) is x>= 2