What is the domain of f(x)=sqrt(x^2+2x+5) ?

The domain of f(x)=sqrt(x^2+2x+5) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2+2x+5)

domain

f (x) = x^{2} + 2 x + 5

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x - 5}{x + 8}

∣ x - 2 ∣

f (x) = 2 e^{x}

- x^{2} + 6 x - 8

y = 2 x + 5

What is the domain of f(x)=sqrt(x^2+2x+5) ?
The domain of f(x)=sqrt(x^2+2x+5) is -infinity <x<infinity