What is the domain of f(x)=(x+5)/(x^2-49) ?

The domain of f(x)=(x+5)/(x^2-49) is x 7

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domain of f(x)=(x+5)/(x^2-49)

domain

f (x) = \frac{x + 5}{x ^{2} - 49}

x < - 7 or - 7 < x < 7 or x > 7

Interval Notation

(- \infty, - 7) \cup (- 7, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 7

The function domain

x < - 7 or - 7 < x < 7 or x > 7

f (x) = - 3 + \frac{7}{3} x

f (x) = (x - 2)^{2} + 4

f (x) = x - \frac{128}{x}

f (x) = - (\frac{1}{3})^{x} + 2

f (x) = 3 + x - 1

What is the domain of f(x)=(x+5)/(x^2-49) ?
The domain of f(x)=(x+5)/(x^2-49) is x<-7\lor-7<x<7\lor x>7