What is the critical f(x)=x^4-8x^3+16x^2 ?

The critical f(x)=x^4-8x^3+16x^2 is x=0,x=2,x=4

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critical f(x)=x^4-8x^3+16x^2

critical points

f (x) = x^{4} - 8 x^{3} + 16 x^{2}

x = 0, x = 2, x = 4

Solution steps

x^{4} - 8 x^{3} + 16 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 8 x^{3} + 16 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 2, x = 4

f (x) = \frac{x}{5}

f (x) = - 2 x - 1 + 1

e^{x - 3} + 2

f (x) = x + 4 - 3

What is the critical f(x)=x^4-8x^3+16x^2 ?
The critical f(x)=x^4-8x^3+16x^2 is x=0,x=2,x=4