What is the extreme f(x)=x^3+3x^2-9x+3 ?

The extreme f(x)=x^3+3x^2-9x+3 is Maximum(-3,30),Minimum(1,-2)

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extreme f(x)=x^3+3x^2-9x+3

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 3

Maximum (- 3, 30), Minimum (1, - 2)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 3 : 30

Maximum (- 3, 30)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 3 : - 2

Minimum (1, - 2)

Maximum (- 3, 30), Minimum (1, - 2)

f (x) = \frac{( x + 1 )}{( x + 9 )}

- sin (x)

f (x) = \frac{x}{5 x + 4}

f (x) = 12

(- 2.1) (1.4)

What is the extreme f(x)=x^3+3x^2-9x+3 ?
The extreme f(x)=x^3+3x^2-9x+3 is Maximum(-3,30),Minimum(1,-2)