What is the shift y=120sin(20pit-pi/2) ?

The shift y=120sin(20pit-pi/2) is Phase: 1/40 , Vertical:0

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shift y=120sin(20pit-pi/2)

shift

y = 120 sin (20 π t - \frac{π}{2})

Phase : \frac{1}{40}, Vertical : 0

Solution steps

f (x) = 120 sin (20 π t - \frac{π}{2})

g (B x - C) = sin (20 π t - \frac{π}{2}), B = 20 π, C = \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{2}}{20 π}

\frac{1}{40}

The vertical shift

D

0

0

f (x) = \frac{- 3}{x + 9} - 6

y = 487

f (x) = \frac{1}{x ^{3}} - 2

y = x^{2} + 4 x - 1

- \frac{1}{2 3 - x}

What is the shift y=120sin(20pit-pi/2) ?
The shift y=120sin(20pit-pi/2) is Phase: 1/40 , Vertical:0