en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=4x^2+2

Solution

range

f (x) = 4 x^{2} + 2

Solution

f (x) \geq 2

+1

Interval Notation

[2, \infty)

Solution steps

Vertex of

4 x^{2} + 2 :

Minimum

(0, 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 4,

Vertex

(x_{v}, y_{v}) = (0, 2)

f (x) \geq 2

Popular Examples

asymptotes of y=10^x asymptotes

y = 1 0^{x}

intercepts of f(x)=x^2+2x-7 intercepts

f (x) = x^{2} + 2 x - 7

inverse of 3/(x+6)inverse

\frac{3}{x + 6}

domain of f(x)=(3x-3)/(sqrt(-x^2+2x+3))domain

f (x) = \frac{3 x - 3}{- x ^{2} + 2 x + 3}

domain of 3/((x+2)(x-1))domain

\frac{3}{( x + 2 ) ( x - 1 )}

Frequently Asked Questions (FAQ)

What is the range of f(x)=4x^2+2 ?
The range of f(x)=4x^2+2 is f(x)>= 2