What is the extreme f(x)=x^3-12x+7 ?

The extreme f(x)=x^3-12x+7 is Maximum(-2,23),Minimum(2,-9)

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extreme f(x)=x^3-12x+7

extreme points

f (x) = x^{3} - 12 x + 7

Maximum (- 2, 23), Minimum (2, - 9)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 7 : 23

Maximum (- 2, 23)

Plug

x = 2

into

x^{3} - 12 x + 7 : - 9

Minimum (2, - 9)

Maximum (- 2, 23), Minimum (2, - 9)

f (x) = x^{3} - 9 x^{2} + 5

\frac{5 x + 1}{7 x + 9}

f (x) = 2 x + 5 y = 20

f (x) = 6 - 5 x^{3}

What is the extreme f(x)=x^3-12x+7 ?
The extreme f(x)=x^3-12x+7 is Maximum(-2,23),Minimum(2,-9)