What is the shift f(t)=sin(2t-pi/3)-4 ?

The shift f(t)=sin(2t-pi/3)-4 is Phase: pi/6 , Vertical:-4

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shift f(t)=sin(2t-pi/3)-4

shift

f (t) = sin (2 t - \frac{π}{3}) - 4

Phase : \frac{π}{6}, Vertical : - 4

Solution steps

f (x) = sin (2 t - \frac{π}{3}) - 4

g (B x - C) = sin (2 t - \frac{π}{3}), B = 2, C = \frac{π}{3}, D = - 4

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{3}}{2}

\frac{π}{6}

The vertical shift

D

- 4

- 4

f (x) = \frac{x ^{2} - 5 x - 3}{2 x + 1}

\frac{x - 1}{x ^{2} + 11 x + 10}

f (x) = 3 x - 1

f (x) = - 5 x + 30

\frac{1}{( x - 1 )}

What is the shift f(t)=sin(2t-pi/3)-4 ?
The shift f(t)=sin(2t-pi/3)-4 is Phase: pi/6 , Vertical:-4