What is the critical f(x)=(x-4)^3 ?

The critical f(x)=(x-4)^3 is x=4

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critical f(x)=(x-4)^3

critical points

f (x) = (x - 4)^{3}

x = 4

Solution steps

(x - 4)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4

Identify critical points not in

f (x)

domain

Domain of

(x - 4)^{3} : - \infty < x < \infty

All critical points are in domain

x = 4

y = x^{2} - 2 x + 3

y = 3^{x + 1} - 4

x (x^{2} - 4)

f (x) = \frac{7}{x ^{2}}

y = x^{4} - 9 x^{2}