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Popular >

distance (-3,-1),(-4,-0)

Solution

distance

(- 3, - 1), (- 4, - 0)

Solution

2

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 3, - 1)

and

(- 4, - 0)

is

= (- 4 - (- 3))^{2} + (- 0 - (- 1))^{2}

Simplify

= 2

Popular Examples

vertices y=x^2+4x-5 vertices

y = x^{2} + 4 x - 5

range of y=(-3)/(12-x-x^2)range

y = \frac{- 3}{12 - x - x ^{2}}

inverse of y= x/(x-2)inverse

y = \frac{x}{x - 2}

domain of f(x)= 7/(4-2x)domain

f (x) = \frac{7}{4 - 2 x}

domain of g(x)=(2x)/(sqrt(x^2+2x-24))domain

g (x) = \frac{2 x}{x ^{2} + 2 x - 24}

Frequently Asked Questions (FAQ)

What is the distance (-3,-1),(-4,-0) ?
The distance (-3,-1),(-4,-0) is square root of 2