What is the inverse of f(x)=x^2+3*x+2 ?

The inverse of f(x)=x^2+3*x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2

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inverse of f(x)=x^2+3*x+2

inverse

f (x) = x^{2} + 3 \cdot x + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

Solution steps

y = x^{2} + 3 x + 2

Replace

x

with

y

x = y^{2} + 3 y + 2

Solve for

y, x = y^{2} + 3 \cdot y + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

f (x) = x^{2} - 10

f (x) = \frac{8}{3 x + 1}

20 x - 4

- \frac{cos ( \frac{11 π x}{6} )}{2} - 2

What is the inverse of f(x)=x^2+3*x+2 ?
The inverse of f(x)=x^2+3*x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2