What is the perpendicular 3y=x-6,(5,-5) ?

The perpendicular 3y=x-6,(5,-5) is y=-3x+10

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perpendicular 3y=x-6,(5,-5)

perpendicular

3 y = x - 6, (5, - 5)

y = - 3 x + 10

Solution steps

Find the line

y = mx + b

perpendicular to

3 y = x - 6

that passes through

(5, - 5)

Find the slope of

3 y = x - 6 : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Find the line with slope m=

- 3

and passing through

(5, - 5) : y = - 3 x + 10

y = - 3 x + 10

8 x + 3 y = - 9

4^{x + 2} - 2

e^{x}

f (x) = \frac{6 - 4 x}{20 x - 1}

f (x) = \frac{1 - 5 x}{6 + x}

What is the perpendicular 3y=x-6,(5,-5) ?
The perpendicular 3y=x-6,(5,-5) is y=-3x+10