What is the range of f(x)=((x^2-25))/((x+5)) ?

The range of f(x)=((x^2-25))/((x+5)) is f(x) -10

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range of f(x)=((x^2-25))/((x+5))

range

f (x) = \frac{( x ^{2} - 25 )}{( x + 5 )}

f (x) < - 10 or f (x) > - 10

Interval Notation

(- \infty, - 10) \cup (- 10, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x ^{2} - 25}{x + 5} : x < - 5 or x > - 5

Simplify

\frac{x ^{2} - 25}{x + 5} : x - 5

Extreme Points of

x - 5 :

None

Find the range for the interval

- \infty < x < - 5 : - \infty < f (x) < - 10

Find the range for the interval

- 5 < x < \infty : - 10 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) < - 10 or f (x) > - 10

f (x) < - 10 or f (x) > - 10

f (x) = 3 x^{\frac{1}{2}}

f (x) = x^{2} - 8

f (x) = \frac{2}{1 - x}

f (x) = \frac{( 4 x ^{3} )}{x - 5}

f (x) = 5 - 4 x^{3}

What is the range of f(x)=((x^2-25))/((x+5)) ?
The range of f(x)=((x^2-25))/((x+5)) is f(x)<-10\lor f(x)>-10