What is the range of f(x)=2\sqrt[3]{x}-4 ?

The range of f(x)=2\sqrt[3]{x}-4 is -infinity <f(x)<infinity

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range of f(x)=2\sqrt[3]{x}-4

range

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

\frac{x ^{3}}{8} + \frac{3 x ^{2}}{2} + 6 x + 8

Find the domain of each inverse function

Domain of

\frac{x ^{3}}{8} + \frac{3 x ^{2}}{2} + 6 x + 8 : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

(4, 4), (- 2, - 4)

9 x^{2} + 6 y^{2} = 3

y = \frac{( x - 4 )}{- 2 x + 12}

f (x) = (x - 2)^{2} - 7

(x - 3)^{2} - 9

What is the range of f(x)=2\sqrt[3]{x}-4 ?
The range of f(x)=2\sqrt[3]{x}-4 is -infinity <f(x)<infinity