What is the slope ofintercept y+4=(-7/8)(x-7) ?

The slope ofintercept y+4=(-7/8)(x-7) is y=-7/8 x+17/8

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slope ofintercept y+4=(-7/8)(x-7)

slope intercept

y + 4 = (- \frac{7}{8}) (x - 7)

y = - \frac{7}{8} x + \frac{17}{8}

Solution steps

y + 4 = (- \frac{7}{8}) (x - 7)

Convert to slope intercept form:

y = - \frac{7}{8} x + \frac{17}{8}

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - \frac{7}{8} x + \frac{17}{8}

2 x^{2} + x - 8

f (x) = \frac{6}{x}

(0, - 2), (- 5, 3)

\frac{x ^{2} + 5}{x ^{2} - 2 x - 15}

f (x) = ln (x) + ln (9 - x)

What is the slope ofintercept y+4=(-7/8)(x-7) ?
The slope ofintercept y+4=(-7/8)(x-7) is y=-7/8 x+17/8