What is the critical x^3+3(27-3x^2)^2+7 ?

The critical x^3+3(27-3x^2)^2+7 is x=(-1-sqrt(46657))/(72),x=0,x=(-1+sqrt(46657))/(72)

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critical x^3+3(27-3x^2)^2+7

critical points

x^{3} + 3 (27 - 3 x^{2})^{2} + 7

x = \frac{- 1 - 46657}{72}, x = 0, x = \frac{- 1 + 46657}{72}

Solution steps

x^{3} + 3 (27 - 3 x^{2})^{2} + 7

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{- 1 - 46657}{72}, x = 0, x = \frac{- 1 + 46657}{72}

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 3 (27 - 3 x^{2})^{2} + 7 : - \infty < x < \infty

All critical points are in domain

x = \frac{- 1 - 46657}{72}, x = 0, x = \frac{- 1 + 46657}{72}

(2, 3), (- 5, - 7)

4 x + 5 y = 7

f (x) = - 9 x^{5} + 6 + x^{2}

f (x) = 0

y = x^{4} - 16 x^{2}

What is the critical x^3+3(27-3x^2)^2+7 ?
The critical x^3+3(27-3x^2)^2+7 is x=(-1-sqrt(46657))/(72),x=0,x=(-1+sqrt(46657))/(72)