What is the domain of (32)/y-(y+1)/(y+7) ?

The domain of (32)/y-(y+1)/(y+7) is y 0

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domain of (32)/y-(y+1)/(y+7)

domain

\frac{32}{y} - \frac{y + 1}{y + 7}

y < - 7 or - 7 < y < 0 or y > 0

Interval Notation

(- \infty, - 7) \cup (- 7, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

y = 0, y = - 7

The function domain

y < - 7 or - 7 < y < 0 or y > 0

\frac{x - 3}{x - 4}

x^{2} - 4 x

f (x) = 2 x^{3} + 15 x^{2} + 7 x

3 sin (x)

4 y + 16 = 0

What is the domain of (32)/y-(y+1)/(y+7) ?
The domain of (32)/y-(y+1)/(y+7) is y<-7\lor-7<y<0\lor y>0