What is the amplitude of-6cos(-4x-pi/8) ?

The amplitude of-6cos(-4x-pi/8) is 6

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amplitude of-6cos(-4x-pi/8)

amplitude

- 6 cos (- 4 x - \frac{π}{8})

6

Solution steps

f (x) = - 6 cos (- 4 x - \frac{π}{8}), A = - 6

Therefore, the amplitude |A| is

6

6

f (x) = (2 x + 1) e^{3 x}

2 x^{2} - 5

f (x) = 5 x - 15 x^{\frac{1}{3}}

\frac{x - 4}{x ^{2} - 16}

f (x) = \frac{- 5 x - 6}{- 15 x - 28}