What is the critical f(x)= x/(x^2-x+1) ?

The critical f(x)= x/(x^2-x+1) is x=-1,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)= x/(x^2-x+1)

critical points

f (x) = \frac{x}{x ^{2} - x + 1}

x = - 1, x = 1

Solution steps

\frac{x}{x ^{2} - x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} - x + 1} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

f (x) = sec (\frac{1}{x})

x^{5} + 3 x^{4} - 25 x^{3} - 79 x^{2} + 100

f (x) = \frac{1}{x - 2} - 3

2 x + 7 y = 9, (- 5, - 1)

g (x) = \frac{4}{x + 3} + 1

What is the critical f(x)= x/(x^2-x+1) ?
The critical f(x)= x/(x^2-x+1) is x=-1,x=1