What is the domain of f(x)=(2x^2-3)/((x^2-9)(x^2-4)) ?

The domain of f(x)=(2x^2-3)/((x^2-9)(x^2-4)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x^2-3)/((x^2-9)(x^2-4))

domain

f (x) = \frac{2 x ^{2} - 3}{( x ^{2} - 9 ) ( x ^{2} - 4 )}

x < - 3 or - 3 < x < - 2 or - 2 < x < 2 or 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, - 2) \cup (- 2, 2) \cup (2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = 3, x = - 2, x = 2

The function domain

x < - 3 or - 3 < x < - 2 or - 2 < x < 2 or 2 < x < 3 or x > 3

\frac{4}{3 - x}

f (x) = 5 x + 7

\frac{4}{3}

(- 1, 4), (- 4, 1)

0.8 3.7 (x + 7) + 5.3

What is the domain of f(x)=(2x^2-3)/((x^2-9)(x^2-4)) ?
The domain of f(x)=(2x^2-3)/((x^2-9)(x^2-4)) is x<-3\lor-3<x<-2\lor-2<x<2\lor 2<x<3\lor x>3