What is the inverse of f(x)=((2x-1))/(x+3) ?

The inverse of f(x)=((2x-1))/(x+3) is (-1-3x)/(x-2)

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inverse of f(x)=((2x-1))/(x+3)

inverse

f (x) = \frac{( 2 x - 1 )}{x + 3}

\frac{- 1 - 3 x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 3}

Replace

x

with

y

x = \frac{2 y - 1}{y + 3}

Solve for

y, x = \frac{2 y - 1}{y + 3}

\frac{- 1 - 3 x}{x - 2}

h (x) = x - 10

f (x) = \frac{2}{4 x - 3}

f (x) = \frac{4 x}{2 x + 3}

\frac{x - 2}{2 x ^{4} - x ^{3} + 4 x - 3}

f (x) = 5 x - 2

What is the inverse of f(x)=((2x-1))/(x+3) ?
The inverse of f(x)=((2x-1))/(x+3) is (-1-3x)/(x-2)