What is the domain of y= 4/((2x^2-7x-4)) ?

The domain of y= 4/((2x^2-7x-4)) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y= 4/((2x^2-7x-4))

domain

y = \frac{4}{( 2 x ^{2} - 7 x - 4 )}

x < - \frac{1}{2} or - \frac{1}{2} < x < 4 or x > 4

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < 4 or x > 4

f (x) = x^{2} + 64

f (x) = (\frac{1}{2 - x}) + (\frac{3}{x + 4})

(8, 6), (1, - 6)

x^{2} - 6 x - 1

\frac{5 x - 3}{2 x + 5}

What is the domain of y= 4/((2x^2-7x-4)) ?
The domain of y= 4/((2x^2-7x-4)) is x<-1/2 \lor-1/2 <x<4\lor x>4