What is the shift f(x)=sin(2x+pi/6) ?

The shift f(x)=sin(2x+pi/6) is Phase:-pi/(12), Vertical:0

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shift f(x)=sin(2x+pi/6)

shift

f (x) = sin (2 x + \frac{π}{6})

Phase : - \frac{π}{12}, Vertical : 0

Solution steps

f (x) = sin (2 x + \frac{π}{6})

g (B x - C) = sin (2 x + \frac{π}{6}), B = 2, C = - \frac{π}{6}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{6}}{2}

- \frac{π}{12}

The vertical shift

D

0

0

f (x) = 2 π r^{2} + \frac{500}{r}

\frac{y ( y - 5 )}{y ^{2} - y + 1}

f (x) = \frac{x + 4}{1 - x}

f (x) = - e^{(- x)} + e^{x}

\frac{- 3 x}{2 x + 5}

What is the shift f(x)=sin(2x+pi/6) ?
The shift f(x)=sin(2x+pi/6) is Phase:-pi/(12), Vertical:0