What is the domain of y=(x^2+x-1)/x ?

The domain of y=(x^2+x-1)/x is x 0

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domain of y=(x^2+x-1)/x

domain

y = \frac{x ^{2} + x - 1}{x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{x}{x ^{2} - 5 x - 14}

y = 5 x + 5

f (x) = 11 - x^{2}, x \geq 0

f (x) = x^{2} + 9

f (x) = (x - 11)^{2}

What is the domain of y=(x^2+x-1)/x ?
The domain of y=(x^2+x-1)/x is x<0\lor x>0