What is the domain of-(19)/((3+t)^2) ?

The domain of-(19)/((3+t)^2) is t -3

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domain of-(19)/((3+t)^2)

domain

- \frac{19}{( 3 + t ) ^{2}}

t < - 3 or t > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

t = - 3

The function domain

t < - 3 or t > - 3

x - 2 y = 3

\frac{5 x}{6 x - 1}

\frac{x ^{3}}{1 - 2 x ^{3}}

f (x) = \frac{x - 4}{1 - x}

f (x) = 8 x + 1

What is the domain of-(19)/((3+t)^2) ?
The domain of-(19)/((3+t)^2) is t<-3\lor t>-3