What is the shift f(x)=-2sin(3x-pi/6)+1 ?

The shift f(x)=-2sin(3x-pi/6)+1 is Phase: pi/(18), Vertical:1

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shift f(x)=-2sin(3x-pi/6)+1

shift

f (x) = - 2 sin (3 x - \frac{π}{6}) + 1

Phase : \frac{π}{18}, Vertical : 1

Solution steps

f (x) = - 2 sin (3 x - \frac{π}{6}) + 1

g (B x - C) = sin (3 x - \frac{π}{6}), B = 3, C = \frac{π}{6}, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{6}}{3}

\frac{π}{18}

The vertical shift

D

1

1

f (x) = \frac{2}{x ^{2} - 2 x - 3}

f (x) = - x^{2}

f (x) = - 9 x + 6

(- 3, 0), (2, 3)

f (x) = 4 x^{2} - 1

What is the shift f(x)=-2sin(3x-pi/6)+1 ?
The shift f(x)=-2sin(3x-pi/6)+1 is Phase: pi/(18), Vertical:1