What is the inverse of f(x)=(x-3)/(2x+1) ?

The inverse of f(x)=(x-3)/(2x+1) is (-3-x)/(2x-1)

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inverse of f(x)=(x-3)/(2x+1)

inverse

f (x) = \frac{x - 3}{2 x + 1}

\frac{- 3 - x}{2 x - 1}

Solution steps

y = \frac{x - 3}{2 x + 1}

Replace

x

with

y

x = \frac{y - 3}{2 y + 1}

Solve for

y, x = \frac{y - 3}{2 y + 1}

\frac{- 3 - x}{2 x - 1}

f (x) = \frac{x + 3}{4 - x}

f (x) = 8 - x^{2}, x \geq 0

\frac{x ^{2} - 2 x - 15}{x}

f (x) = x^{2} - 12

f (x) = \frac{7 x ^{2} - 2 x}{15 x + 5}

What is the inverse of f(x)=(x-3)/(2x+1) ?
The inverse of f(x)=(x-3)/(2x+1) is (-3-x)/(2x-1)