What is the domain of f(x)=(2x^2-x-3)/(x^2+1) ?

The domain of f(x)=(2x^2-x-3)/(x^2+1) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x^2-x-3)/(x^2+1)

domain

f (x) = \frac{2 x ^{2} - x - 3}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

3 x + y = 6

2 x^{3} + 4

y - 2 = - x

f (x) = x + sin (x)

f (x) = \frac{1}{- n - 1} + 2

What is the domain of f(x)=(2x^2-x-3)/(x^2+1) ?
The domain of f(x)=(2x^2-x-3)/(x^2+1) is -infinity <x<infinity