What is the inverse of f(x)=3\sqrt[3]{x}+2 ?

The inverse of f(x)=3\sqrt[3]{x}+2 is (x^3}{27}-\frac{2x^2)/9+(4x)/9-8/27

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inverse of f(x)=3\sqrt[3]{x}+2

inverse

\frac{x ^{3}}{27} - \frac{2 x ^{2}}{9} + \frac{4 x}{9} - \frac{8}{27}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{27} - \frac{2 x ^{2}}{9} + \frac{4 x}{9} - \frac{8}{27}

lo g_{2} (4 x)

\frac{1 + 3 x}{5 - 2 x}

(2, - 5), (8, 3)

(- 4, - 2), (0.5, 0)

f = \frac{1}{3} f (6) = 6

What is the inverse of f(x)=3\sqrt[3]{x}+2 ?
The inverse of f(x)=3\sqrt[3]{x}+2 is (x^3}{27}-\frac{2x^2)/9+(4x)/9-8/27