What is the inflection f(x)= 6/(x^2+3) ?

The inflection f(x)= 6/(x^2+3) is (-1, 3/2),(1, 3/2)

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inflection f(x)= 6/(x^2+3)

inflection points

f (x) = \frac{6}{x ^{2} + 3}

(- 1, \frac{3}{2}), (1, \frac{3}{2})

Solution steps

f^{''} (x) = - \frac{36 ( - x ^{2} + 1 )}{( x ^{2} + 3 ) ^{3}}

Find intervals:

Concave Upward

: - \infty < x < - 1,

Concave Downward

: - 1 < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = - 1

into

\frac{6}{x ^{2} + 3} : \frac{3}{2}

(- 1, \frac{3}{2})

Plug

x = 1

into

\frac{6}{x ^{2} + 3} : \frac{3}{2}

(1, \frac{3}{2})

(- 1, \frac{3}{2}), (1, \frac{3}{2})

f (x) = x e^{- x}

cos (2) (x - \frac{π}{2})

f (x) = \frac{( x )}{( 4 - x ^{2} )}

x^{3} - 3 x + 3

2 x - 2

What is the inflection f(x)= 6/(x^2+3) ?
The inflection f(x)= 6/(x^2+3) is (-1, 3/2),(1, 3/2)