What is the perpendicular y=-5x+2,\at x=1 ?

The perpendicular y=-5x+2,\at x=1 is y= 1/5 x-16/5

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perpendicular y=-5x+2,\at x=1

perpendicular

y = - 5 x + 2, at x = 1

y = \frac{1}{5} x - \frac{16}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 5 x + 2

that passes through

x = 1

Find the perpendicular point:

(1, - 3)

Find the slope of

y = - 5 x + 2 : m = - 5

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{5}

Find the line with slope m=

\frac{1}{5}

and passing through

(1, - 3) : y = \frac{1}{5} x - \frac{16}{5}

y = \frac{1}{5} x - \frac{16}{5}

f (x) = x^{3} + 3 x^{2} + 3 x + 3

f (x) = \frac{x}{x - 6}

\frac{x + 4}{x - 5}

f (x) = - 6 x - 2

y = 2 x^{2} - 12 x + 9

What is the perpendicular y=-5x+2,\at x=1 ?
The perpendicular y=-5x+2,\at x=1 is y= 1/5 x-16/5