What is the perpendicular 9x-8y-16=0 ?

The perpendicular 9x-8y-16=0 is y=-8/9 x+b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular 9x-8y-16=0

perpendicular

9 x - 8 y - 16 = 0

y = - \frac{8}{9} x + b

Solution steps

Find the slope of

9 x - 8 y - 16 = 0 : m = \frac{9}{8}

Compute the slope of the perpendicular line:

m_{p} = - \frac{8}{9}

Line with slope m=

- \frac{8}{9} : y = - \frac{8}{9} x + b

y = - \frac{8}{9} x + b

y = 6 x + 1

f (x) = \frac{x}{x ^{2} + 1}

3 - \frac{6}{x}

f (x) = - 0.1 x^{2} + 1.2 x + 98.6

(5.7) (5.14)

What is the perpendicular 9x-8y-16=0 ?
The perpendicular 9x-8y-16=0 is y=-8/9 x+b