What is the domain of f(x)= 1/(\sqrt[4]{x^2-2x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-2x)} is x 2

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domain of f(x)= 1/(\sqrt[4]{x^2-2x)}

domain

x < 0 or x > 2

Interval Notation

(- \infty, 0) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 2

arctan (x)

f (x) = x + 3 x - 18

f (x) = x \cdot e^{- x}

\frac{( 2 x ^{2} - 6 x + 4 )}{x ^{2} - 5 x + 4}

f (x) = \frac{x}{x + 1}

What is the domain of f(x)= 1/(\sqrt[4]{x^2-2x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-2x)} is x<0\lor x>2