What is the domain of (x+3)^2(2x-12)^{1/4} ?

The domain of (x+3)^2(2x-12)^{1/4} is x>= 6

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domain of (x+3)^2(2x-12)^{1/4}

domain

(x + 3)^{2} (2 x - 12)^{\frac{1}{4}}

x \geq 6

Interval Notation

[6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 6

The function domain

x \geq 6

\frac{5 x + 25}{x}

f (x) = \frac{x ^{2} - 5}{2 x ^{2} - 18}

f (x) = x + ∣ x ∣

x^{3} + 1

4^{x}

What is the domain of (x+3)^2(2x-12)^{1/4} ?
The domain of (x+3)^2(2x-12)^{1/4} is x>= 6